-36x^2+1875x-650=0

Solution for -36x^2+1875x-650=0 equation:

-36x^2+1875x-650=0

a = -36; b = 1875; c = -650;
Δ = b2-4ac
Δ = 18752-4·(-36)·(-650)
Δ = 3422025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3422025}=\sqrt{225*15209}=\sqrt{225}*\sqrt{15209}=15\sqrt{15209}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1875)-15\sqrt{15209}}{2*-36}=\frac{-1875-15\sqrt{15209}}{-72}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1875)+15\sqrt{15209}}{2*-36}=\frac{-1875+15\sqrt{15209}}{-72}
$